Starting with Data
Overview
Teaching: 50 min
Exercises: 30 minQuestions
What is a data.frame?
How can I read a complete csv file into R?
How can I get basic summary information about my dataset?
How can I change the way R treats strings in my dataset?
Why would I want strings to be treated differently?
How are dates represented in R and how can I change the format?
Objectives
Describe what a data frame is.
Load external data from a .csv file into a data frame.
Summarize the contents of a data frame.
Subset and extract values from data frames.
Describe the difference between a factor and a string.
Convert between strings and factors.
Reorder and rename factors.
Change how character strings are handled in a data frame.
Examine and change date formats.
What are data frames and tibbles?
Data frames are the de facto data structure for tabular data in R
, and what
we use for data processing, statistics, and plotting.
A data frame is the representation of data in the format of a table where the columns are vectors that all have the same length. Data frames are analogous to the more familiar spreadsheet in programs such as Excel, with one key difference. Because columns are vectors, each column must contain a single type of data (e.g., characters, integers, factors). For example, here is a figure depicting a data frame comprising a numeric, a character, and a logical vector.
A data frame can be created by hand, but most commonly they are generated by the
functions read_csv()
or read_table()
; in other words, when importing
spreadsheets from your hard drive (or the web). We will now demonstrate how to
import tabular data using read_csv()
.
Presentation of the SAFI Data
SAFI (Studying African Farmer-Led Irrigation) is a study looking at farming and irrigation methods in Tanzania and Mozambique. The survey data was collected through interviews conducted between November 2016 and June 2017. For this lesson, we will be using a subset of the available data. For information about the full teaching dataset used in other lessons in this workshop, see the dataset description.
We will be using a subset of the cleaned version of the dataset that
was produced through cleaning in OpenRefine (data/SAFI_clean.csv
). Each row holds
information for a single interview respondent, and the columns
represent:
column_name | description |
---|---|
key_id | Added to provide a unique Id for each observation. (The InstanceID field does this as well but it is not as convenient to use) |
village | Village name |
interview_date | Date of interview |
no_membrs | How many members in the household? |
years_liv | How many years have you been living in this village or neighboring village? |
respondent_wall_type | What type of walls does their house have (from list) |
rooms | How many rooms in the main house are used for sleeping? |
memb_assoc | Are you a member of an irrigation association? |
affect_conflicts | Have you been affected by conflicts with other irrigators in the area? |
liv_count | Number of livestock owned. |
items_owned | Which of the following items are owned by the household? (list) |
no_meals | How many meals do people in your household normally eat in a day? |
months_lack_food | Indicate which months, In the last 12 months have you faced a situation when you did not have enough food to feed the household? |
instanceID | Unique identifier for the form data submission |
You are going load the data in R’s memory using the function read_csv()
from the readr
package, which is part of the tidyverse
; learn
more about the tidyverse
collection of packages
here.
readr
gets installed as part as the tidyverse
installation.
When you load the tidyverse
(library(tidyverse)
), the core packages
(the packages used in most data analyses) get loaded, including readr
.
So, before we can use the read_csv()
function, we need to load the package.
Also, if you recall, the missing data is encoded as “NULL” in the dataset.
We’ll tell it to the function, so R will automatically convert all the “NULL”
entries in the dataset into NA
.
library(tidyverse)
interviews <- read_csv("data/SAFI_clean.csv", na = "NULL")
If you were to type in the code above, it is likely that the read.csv()
function would appear in the automatically populated list of functions. This
function is different from the read_csv()
function, as it is included in the
“base” packages that come pre-installed with R. Overall, read.csv()
behaves
similar to read_csv()
, with a few notable differences. First, read.csv()
coerces column names with spaces and/or special characters to different names
(e.g. interview date
becomes interview.date
). Second, read.csv()
stores data as a data.frame
, where read_csv()
stores data as a tibble
.
We prefer tibbles because they have nice printing properties among other
desirable qualities. Read more about tibbles here.
The second statement in the code above creates a data frame but doesn’t output
any data because, as you might recall, assignments (<-
) don’t display
anything. (Note, however, that read_csv
may show informational
text about the data frame that is created.) If we want to check that our data
has been loaded, we can see the contents of the data frame by typing its name:
interviews
in the console.
interviews
## Try also
## view(interviews)
## head(interviews)
# A tibble: 131 × 14
key_ID village interview_date no_membrs years_liv respo…¹ rooms memb_…²
<dbl> <chr> <dttm> <dbl> <dbl> <chr> <dbl> <chr>
1 1 God 2016-11-17 00:00:00 3 4 muddaub 1 <NA>
2 1 God 2016-11-17 00:00:00 7 9 muddaub 1 yes
3 3 God 2016-11-17 00:00:00 10 15 burntb… 1 <NA>
4 4 God 2016-11-17 00:00:00 7 6 burntb… 1 <NA>
5 5 God 2016-11-17 00:00:00 7 40 burntb… 1 <NA>
6 6 God 2016-11-17 00:00:00 3 3 muddaub 1 <NA>
7 7 God 2016-11-17 00:00:00 6 38 muddaub 1 no
8 8 Chirodzo 2016-11-16 00:00:00 12 70 burntb… 3 yes
9 9 Chirodzo 2016-11-16 00:00:00 8 6 burntb… 1 no
10 10 Chirodzo 2016-12-16 00:00:00 12 23 burntb… 5 no
# … with 121 more rows, 6 more variables: affect_conflicts <chr>,
# liv_count <dbl>, items_owned <chr>, no_meals <dbl>, months_lack_food <chr>,
# instanceID <chr>, and abbreviated variable names ¹respondent_wall_type,
# ²memb_assoc
Note
read_csv()
assumes that fields are delimited by commas. However, in several countries, the comma is used as a decimal separator and the semicolon (;) is used as a field delimiter. If you want to read in this type of files in R, you can use theread_csv2
function. It behaves exactly likeread_csv
but uses different parameters for the decimal and the field separators. If you are working with another format, they can be both specified by the user. Check out the help forread_csv()
by typing?read_csv
to learn more. There is also theread_tsv()
for tab-separated data files, andread_delim()
allows you to specify more details about the structure of your file.
Note that read_csv()
actually loads the data as a tibble.
A tibble is an extension of R
data frames used by the tidyverse
. When the
data is read using read_csv()
, it is stored in an object of class tbl_df
,
tbl
, and data.frame
. You can see the class of an object with
class(interviews)
[1] "spec_tbl_df" "tbl_df" "tbl" "data.frame"
As a tibble
, the type of data included in each column is listed in an
abbreviated fashion below the column names. For instance, here key_ID
is a
column of floating point numbers (abbreviated <dbl>
for the word ‘double’),
village
is a column of characters (<chr>
) and the interview_date
is a
column in the “date and time” format (<dttm>
).
Inspecting data frames
When calling a tbl_df
object (like interviews
here), there is already a lot of information about our data frame being displayed such as the number of rows, the number of columns, the names of the columns, and as we just saw the class of data stored in each column. However, there are functions to extract this information from data frames. Here is a non-exhaustive list of some of these
functions. Let’s try them out!
Size:
dim(interviews)
- returns a vector with the number of rows as the first element, and the number of columns as the second element (the dimensions of the object)nrow(interviews)
- returns the number of rowsncol(interviews)
- returns the number of columns
Content:
head(interviews)
- shows the first 6 rowstail(interviews)
- shows the last 6 rows
Names:
names(interviews)
- returns the column names (synonym ofcolnames()
fordata.frame
objects)
Summary:
str(interviews)
- structure of the object and information about the class, length and content of each columnsummary(interviews)
- summary statistics for each columnglimpse(interviews)
- returns the number of columns and rows of the tibble, the names and class of each column, and previews as many values will fit on the screen. Unlike the other inspecting functions listed above,glimpse()
is not a “base R” function so you need to have thedplyr
ortibble
packages loaded to be able to execute it.
Note: most of these functions are “generic.” They can be used on other types of objects besides data frames or tibbles.
Indexing and subsetting data frames
Our interviews
data frame has rows and columns (it has 2 dimensions).
In practice, we may not need the entire data frame; for instance, we may only
be interested in a subset of the observations (the rows) or a particular set
of variables (the columns). If we want to
extract some specific data from it, we need to specify the “coordinates” we
want from it. Row numbers come first, followed by column numbers.
Tip
Indexing a
tibble
with[
or[[
or$
always results in atibble
. However, note this is not true in general for data frames, so be careful! Different ways of specifying these coordinates can lead to results with different classes. This is covered in the Software Carpentry lesson R for Reproducible Scientific Analysis.
## first element in the first column of the tibble
interviews[1, 1]
# A tibble: 1 × 1
key_ID
<dbl>
1 1
## first element in the 6th column of the tibble
interviews[1, 6]
# A tibble: 1 × 1
respondent_wall_type
<chr>
1 muddaub
## first column of the tibble (as a vector)
interviews[[1]]
[1] 1 1 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
[19] 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36
[37] 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 21 54
[55] 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 127
[73] 133 152 153 155 178 177 180 181 182 186 187 195 196 197 198 201 202 72
[91] 73 76 83 85 89 101 103 102 78 80 104 105 106 109 110 113 118 125
[109] 119 115 108 116 117 144 143 150 159 160 165 166 167 174 175 189 191 192
[127] 126 193 194 199 200
## first column of the tibble
interviews[1]
# A tibble: 131 × 1
key_ID
<dbl>
1 1
2 1
3 3
4 4
5 5
6 6
7 7
8 8
9 9
10 10
# … with 121 more rows
## first three elements in the 7th column of the tibble
interviews[1:3, 7]
# A tibble: 3 × 1
rooms
<dbl>
1 1
2 1
3 1
## the 3rd row of the tibble
interviews[3, ]
# A tibble: 1 × 14
key_ID village interview_date no_membrs years_liv respond…¹ rooms memb_…²
<dbl> <chr> <dttm> <dbl> <dbl> <chr> <dbl> <chr>
1 3 God 2016-11-17 00:00:00 10 15 burntbri… 1 <NA>
# … with 6 more variables: affect_conflicts <chr>, liv_count <dbl>,
# items_owned <chr>, no_meals <dbl>, months_lack_food <chr>,
# instanceID <chr>, and abbreviated variable names ¹respondent_wall_type,
# ²memb_assoc
## equivalent to head_interviews <- head(interviews)
head_interviews <- interviews[1:6, ]
:
is a special function that creates numeric vectors of integers in increasing
or decreasing order, test 1:10
and 10:1
for instance.
You can also exclude certain indices of a data frame using the “-
” sign:
interviews[, -1] # The whole tibble, except the first column
# A tibble: 131 × 13
village interview_date no_membrs years_…¹ respo…² rooms memb_…³ affec…⁴
<chr> <dttm> <dbl> <dbl> <chr> <dbl> <chr> <chr>
1 God 2016-11-17 00:00:00 3 4 muddaub 1 <NA> <NA>
2 God 2016-11-17 00:00:00 7 9 muddaub 1 yes once
3 God 2016-11-17 00:00:00 10 15 burntb… 1 <NA> <NA>
4 God 2016-11-17 00:00:00 7 6 burntb… 1 <NA> <NA>
5 God 2016-11-17 00:00:00 7 40 burntb… 1 <NA> <NA>
6 God 2016-11-17 00:00:00 3 3 muddaub 1 <NA> <NA>
7 God 2016-11-17 00:00:00 6 38 muddaub 1 no never
8 Chirodzo 2016-11-16 00:00:00 12 70 burntb… 3 yes never
9 Chirodzo 2016-11-16 00:00:00 8 6 burntb… 1 no never
10 Chirodzo 2016-12-16 00:00:00 12 23 burntb… 5 no never
# … with 121 more rows, 5 more variables: liv_count <dbl>, items_owned <chr>,
# no_meals <dbl>, months_lack_food <chr>, instanceID <chr>, and abbreviated
# variable names ¹years_liv, ²respondent_wall_type, ³memb_assoc,
# ⁴affect_conflicts
interviews[-c(7:131), ] # Equivalent to head(interviews)
# A tibble: 6 × 14
key_ID village interview_date no_membrs years_liv respond…¹ rooms memb_…²
<dbl> <chr> <dttm> <dbl> <dbl> <chr> <dbl> <chr>
1 1 God 2016-11-17 00:00:00 3 4 muddaub 1 <NA>
2 1 God 2016-11-17 00:00:00 7 9 muddaub 1 yes
3 3 God 2016-11-17 00:00:00 10 15 burntbri… 1 <NA>
4 4 God 2016-11-17 00:00:00 7 6 burntbri… 1 <NA>
5 5 God 2016-11-17 00:00:00 7 40 burntbri… 1 <NA>
6 6 God 2016-11-17 00:00:00 3 3 muddaub 1 <NA>
# … with 6 more variables: affect_conflicts <chr>, liv_count <dbl>,
# items_owned <chr>, no_meals <dbl>, months_lack_food <chr>,
# instanceID <chr>, and abbreviated variable names ¹respondent_wall_type,
# ²memb_assoc
tibble
s can be subset by calling indices (as shown previously), but also by calling their column names directly:
interviews["village"] # Result is a tibble
interviews[, "village"] # Result is a tibble
interviews[["village"]] # Result is a vector
interviews$village # Result is a vector
In RStudio, you can use the autocompletion feature to get the full and correct names of the columns.
Exercise
Create a tibble (
interviews_100
) containing only the data in row 100 of theinterviews
dataset.Notice how
nrow()
gave you the number of rows in the tibble?
- Use that number to pull out just that last row in the tibble.
- Compare that with what you see as the last row using
tail()
to make sure it’s meeting expectations.- Pull out that last row using
nrow()
instead of the row number.- Create a new tibble (
interviews_last
) from that last row.Using the number of rows in the interviews dataset that you found in question 2, extract the row that is in the middle of the dataset. Store the content of this middle row in an object named
interviews_middle
. (hint: This dataset has an odd number of rows, so finding the middle is a bit trickier than dividing n_rows by 2. Use the median( ) function and what you’ve learned about sequences in R to extract the middle row!Combine
nrow()
with the-
notation above to reproduce the behavior ofhead(interviews)
, keeping just the first through 6th rows of the interviews dataset.Solution
## 1. interviews_100 <- interviews[100, ] ## 2. # Saving `n_rows` to improve readability and reduce duplication n_rows <- nrow(interviews) interviews_last <- interviews[n_rows, ] ## 3. interviews_middle <- interviews[median(1:n_rows), ] ## 4. interviews_head <- interviews[-(7:n_rows), ]
Factors
R has a special data class, called factor, to deal with categorical data that you may encounter when creating plots or doing statistical analyses. Factors are very useful and actually contribute to making R particularly well suited to working with data. So we are going to spend a little time introducing them.
Factors represent categorical data. They are stored as integers associated with
labels and they can be ordered (ordinal) or unordered (nominal). Factors
create a structured relation between the different levels (values) of a
categorical variable, such as days of the week or responses to a question in
a survey. This can make it easier to see how one element relates to the
other elements in a column. While factors look (and often behave) like
character vectors, they are actually treated as integer vectors by R
. So
you need to be very careful when treating them as strings.
Once created, factors can only contain a pre-defined set of values, known as levels. By default, R always sorts levels in alphabetical order. For instance, if you have a factor with 2 levels:
respondent_floor_type <- factor(c("earth", "cement", "cement", "earth"))
R will assign 1
to the level "cement"
and 2
to the level "earth"
(because c
comes before e
, even though the first element in this vector is
"earth"
). You can see this by using the function levels()
and you can find
the number of levels using nlevels()
:
levels(respondent_floor_type)
[1] "cement" "earth"
nlevels(respondent_floor_type)
[1] 2
Sometimes, the order of the factors does not matter. Other times you might want
to specify the order because it is meaningful (e.g., “low”, “medium”, “high”).
It may improve your visualization, or it may be required by a particular type of
analysis. Here, one way to reorder our levels in the respondent_floor_type
vector would be:
respondent_floor_type # current order
[1] earth cement cement earth
Levels: cement earth
respondent_floor_type <- factor(respondent_floor_type, levels = c("earth", "cement"))
respondent_floor_type # after re-ordering
[1] earth cement cement earth
Levels: earth cement
In R’s memory, these factors are represented by integers (1, 2), but are more
informative than integers because factors are self describing: "cement"
,
"earth"
is more descriptive than 1
, and 2
. Which one is “earth”? You
wouldn’t be able to tell just from the integer data. Factors, on the other hand,
have this information built in. It is particularly helpful when there are many
levels. It also makes renaming levels easier. Let’s say we made a mistake and need to recode “cement” to “brick”.
levels(respondent_floor_type)
[1] "earth" "cement"
levels(respondent_floor_type)[2] <- "brick"
levels(respondent_floor_type)
[1] "earth" "brick"
respondent_floor_type
[1] earth brick brick earth
Levels: earth brick
So far, your factor is unordered, like a nominal variable. R does not know the
difference between a nominal and an ordinal variable. You make your factor an
ordered factor by using the ordered=TRUE
option inside your factor function.
Note how the reported levels changed from the unordered factor above to the
ordered version below. Ordered levels use the less than sign <
to denote
level ranking.
respondent_floor_type_ordered <- factor(respondent_floor_type, ordered=TRUE)
respondent_floor_type_ordered # after setting as ordered factor
[1] earth brick brick earth
Levels: earth < brick
Converting factors
If you need to convert a factor to a character vector, you use
as.character(x)
.
as.character(respondent_floor_type)
[1] "earth" "brick" "brick" "earth"
Converting factors where the levels appear as numbers (such as concentration
levels, or years) to a numeric vector is a little trickier. The as.numeric()
function returns the index values of the factor, not its levels, so it will
result in an entirely new (and unwanted in this case) set of numbers.
One method to avoid this is to convert factors to characters, and then to numbers.
Another method is to use the levels()
function. Compare:
year_fct <- factor(c(1990, 1983, 1977, 1998, 1990))
as.numeric(year_fct) # Wrong! And there is no warning...
[1] 3 2 1 4 3
as.numeric(as.character(year_fct)) # Works...
[1] 1990 1983 1977 1998 1990
as.numeric(levels(year_fct))[year_fct] # The recommended way.
[1] 1990 1983 1977 1998 1990
Notice that in the recommended levels()
approach, three important steps occur:
- We obtain all the factor levels using
levels(year_fct)
- We convert these levels to numeric values using
as.numeric(levels(year_fct))
- We then access these numeric values using the underlying integers of the
vector
year_fct
inside the square brackets
Renaming factors
When your data is stored as a factor, you can use the plot()
function to get a
quick glance at the number of observations represented by each factor level.
Let’s extract the memb_assoc
column from our data frame, convert it into a
factor, and use it to look at the number of interview respondents who were or
were not members of an irrigation association:
## create a vector from the data frame column "memb_assoc"
memb_assoc <- interviews$memb_assoc
## convert it into a factor
memb_assoc <- as.factor(memb_assoc)
## let's see what it looks like
memb_assoc
[1] <NA> yes <NA> <NA> <NA> <NA> no yes no no <NA> yes no <NA> yes
[16] <NA> <NA> <NA> <NA> <NA> no <NA> <NA> no no no <NA> no yes <NA>
[31] <NA> yes no yes yes yes <NA> yes <NA> yes <NA> no no <NA> no
[46] no yes <NA> <NA> yes <NA> no yes no <NA> yes no no <NA> no
[61] yes <NA> <NA> <NA> no yes no no no no yes <NA> no yes <NA>
[76] <NA> yes no no yes no no yes no yes no no <NA> yes yes
[91] yes yes yes no no no no yes no no yes yes no <NA> no
[106] no <NA> no no <NA> no <NA> <NA> no no no no yes no no
[121] no no no no no no no no no yes <NA>
Levels: no yes
## bar plot of the number of interview respondents who were
## members of irrigation association:
plot(memb_assoc)
Looking at the plot compared to the output of the vector, we can see that in addition to “no”s and “yes”s, there are some respondents for which the information about whether they were part of an irrigation association hasn’t been recorded, and encoded as missing data. They do not appear on the plot. Let’s encode them differently so they can counted and visualized in our plot.
## Let's recreate the vector from the data frame column "memb_assoc"
memb_assoc <- interviews$memb_assoc
## replace the missing data with "undetermined"
memb_assoc[is.na(memb_assoc)] <- "undetermined"
## convert it into a factor
memb_assoc <- as.factor(memb_assoc)
## let's see what it looks like
memb_assoc
[1] undetermined yes undetermined undetermined undetermined
[6] undetermined no yes no no
[11] undetermined yes no undetermined yes
[16] undetermined undetermined undetermined undetermined undetermined
[21] no undetermined undetermined no no
[26] no undetermined no yes undetermined
[31] undetermined yes no yes yes
[36] yes undetermined yes undetermined yes
[41] undetermined no no undetermined no
[46] no yes undetermined undetermined yes
[51] undetermined no yes no undetermined
[56] yes no no undetermined no
[61] yes undetermined undetermined undetermined no
[66] yes no no no no
[71] yes undetermined no yes undetermined
[76] undetermined yes no no yes
[81] no no yes no yes
[86] no no undetermined yes yes
[91] yes yes yes no no
[96] no no yes no no
[101] yes yes no undetermined no
[106] no undetermined no no undetermined
[111] no undetermined undetermined no no
[116] no no yes no no
[121] no no no no no
[126] no no no no yes
[131] undetermined
Levels: no undetermined yes
## bar plot of the number of interview respondents who were
## members of irrigation association:
plot(memb_assoc)
Exercise
Rename the levels of the factor to have the first letter in uppercase: “No”,”Undetermined”, and “Yes”.
Now that we have renamed the factor level to “Undetermined”, can you recreate the barplot such that “Undetermined” is last (after “Yes”)?
Solution
levels(memb_assoc) <- c("No", "Undetermined", "Yes") memb_assoc <- factor(memb_assoc, levels = c("No", "Yes", "Undetermined")) plot(memb_assoc)
Formatting Dates
One of the most common issues that new (and experienced!) R users have is
converting date and time information into a variable that is appropriate and
usable during analyses. As a reminder from earlier in this lesson, the best
practice for dealing with date data is to ensure that each component of your
date is stored as a separate variable. In our dataset, we have a
column interview_date
which contains information about the
year, month, and day that the interview was conducted. Let’s
convert those dates into three separate columns.
str(interviews)
We are going to use the package lubridate
, which is included in the
tidyverse
installation but not loaded by default, so we have to load
it explicitly with library(lubridate)
.
Start by loading the required package:
library(lubridate)
The lubridate function ymd()
takes a vector representing year, month, and day, and converts it to a
Date
vector. Date
is a class of data recognized by R as being a date and can
be manipulated as such. The argument that the function requires is flexible,
but, as a best practice, is a character vector formatted as “YYYY-MM-DD”.
Let’s extract our interview_date
column and inspect the structure:
dates <- interviews$interview_date
str(dates)
POSIXct[1:131], format: "2016-11-17" "2016-11-17" "2016-11-17" "2016-11-17" "2016-11-17" ...
When we imported the data in R, read_csv()
recognized that this column contained date information. We can now use the day()
, month()
and year()
functions to extract this information from the date, and create new columns in our data frame to store it:
interviews$day <- day(dates)
interviews$month <- month(dates)
interviews$year <- year(dates)
interviews
# A tibble: 131 × 17
key_ID village interview_date no_membrs years_liv respo…¹ rooms memb_…²
<dbl> <chr> <dttm> <dbl> <dbl> <chr> <dbl> <chr>
1 1 God 2016-11-17 00:00:00 3 4 muddaub 1 <NA>
2 1 God 2016-11-17 00:00:00 7 9 muddaub 1 yes
3 3 God 2016-11-17 00:00:00 10 15 burntb… 1 <NA>
4 4 God 2016-11-17 00:00:00 7 6 burntb… 1 <NA>
5 5 God 2016-11-17 00:00:00 7 40 burntb… 1 <NA>
6 6 God 2016-11-17 00:00:00 3 3 muddaub 1 <NA>
7 7 God 2016-11-17 00:00:00 6 38 muddaub 1 no
8 8 Chirodzo 2016-11-16 00:00:00 12 70 burntb… 3 yes
9 9 Chirodzo 2016-11-16 00:00:00 8 6 burntb… 1 no
10 10 Chirodzo 2016-12-16 00:00:00 12 23 burntb… 5 no
# … with 121 more rows, 9 more variables: affect_conflicts <chr>,
# liv_count <dbl>, items_owned <chr>, no_meals <dbl>, months_lack_food <chr>,
# instanceID <chr>, day <int>, month <dbl>, year <dbl>, and abbreviated
# variable names ¹respondent_wall_type, ²memb_assoc
Notice the three new columns at the end of our data frame.
In our example above, the interview_date
column was read in correctly as a Date
variable but generally that is not the case. Date columns are often read in as character
variables and one can use the as_date()
function to convert them to the appropriate Date/POSIXct
format.
Let’s say we have a vector of dates in character format:
char_dates <- c("7/31/2012","8/9/2014",'4/30/2106')
str(char_dates)
chr [1:3] "7/31/2012" "8/9/2014" "4/30/2106"
We can convert this vector to dates as :
as_date(char_dates, format = "%m/%d/%Y")
[1] "2012-07-31" "2014-08-09" "2106-04-30"
Argument format
tells the function the order to parse the characters and identify the month, day and year. The format above is the equivalent of mm/dd/yyyy. A wrong format can lead to parsing errors or incorrect results.
For example, observe what happens when we use a lower case y instead of upper case Y for the year.
as_date(char_dates, format = "%m/%d/%y")
[1] "2020-07-31" "2020-08-09" "2021-04-30"
Here, the %y
part of the format stands for a two-digit year instead of a four-digit year, and this leads to parsing errors.
Or in the following example, observe what happens when the month and day elements of the format are switched.
as_date(char_dates, format = "%d/%m/%y")
[1] NA "2020-09-08" NA
Since there is no month numbered 30 or 31, the first and third dates cannot be parsed.
We can also use functions ymd()
, mdy()
or dmy()
to convert character variables to date.
mdy(char_dates)
[1] "2012-07-31" "2014-08-09" "2106-04-30"
Key Points
Use read_csv to read tabular data in R.
Use factors to represent categorical data in R.